{"id":231,"date":"2025-09-08T08:05:32","date_gmt":"2025-09-08T08:05:32","guid":{"rendered":"https:\/\/learn-by-animation.com\/?page_id=231"},"modified":"2025-09-08T08:59:34","modified_gmt":"2025-09-08T08:59:34","slug":"thermodynamics-practise-questions","status":"publish","type":"page","link":"https:\/\/learn-by-animation.com\/?page_id=231","title":{"rendered":"Thermodynamics&#8211;Practice Questions"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">The Multiple Choice Questions with solutions are divided into three categories:<\/p>\n\n\n\n<!DOCTYPE html>\n<html lang=\"en\">\n<head>\n  \n  \n  <title>Question Bank<\/title>\n  <style>\n    body { font-family: sans-serif; }\n    .page-container { display: flex; gap: 30px; margin-bottom: 20px; }\n    .main-content { flex: 2; }\n    .explanation { flex: 1; padding: 15px; border: 1px solid #ddd; background: #f9f9f9; }\n    .option { padding: 10px; border: 1px solid #ccc; margin: 5px 0; cursor: pointer; }\n    .correct { background: #d4edda; border-color: #c3e6cb; color: #155724; }\n    .incorrect { background: #f8d7da; border-color: #f5c6cb; color: #721c24; }\n    .hidden { display: none; }\n    details { margin: 10px 0; border: 1px solid #ccc; border-radius: 6px; padding: 8px; background: #fdfdfd; }\n    summary { font-weight: bold; cursor: pointer; padding: 4px; }\n  <\/style>\n<\/head>\n<body>\n\n<h2>Question Bank<\/h2>\n\n<!-- ================= FORMULA-BASED QUESTIONS ================= -->\n<details>\n  <summary>Formula-Based Questions<\/summary>\n\n  <!-- SUB-CATEGORY 1 -->\n  <details>\n    <summary>SI Units Asked<\/summary>\n\n    \n\n    <!-- QUIZ 3 -->\n    <div class=\"page-container\" id=\"quiz3\">\n      <div class=\"main-content\">\n        <p>Q&#8211;2: The SI unit of Electric Field is:<\/p>\n        <div id=\"options3\">\n          <div class=\"option\" data-answer=\"A\">A) Volt\/meter<\/div>\n          <div class=\"option\" data-answer=\"B\">B) Newton<\/div>\n          <div class=\"option\" data-answer=\"C\">C) Joule<\/div>\n          <div class=\"option\" data-answer=\"D\">D) Coulomb<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation3\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: Volt\/meter (same as Newton per coulomb).<\/p>\n      <\/div>\n    <\/div>\n\n  <\/details>\n\n  <!-- SUB-CATEGORY 2 -->\n  <details>\n    <summary>Derived Formulas Asked<\/summary>\n    <!-- QUIZ 2 -->\n    <div class=\"page-container\" id=\"quiz2\">\n      <div class=\"main-content\">\n        <p>Q&#8211;1: Two spheres A and B of radius &#8216;a&#8217; and &#8216;b&#8217; are at same electric potential. The ratio of surface charge densities is:<\/p>\n        <div id=\"options2\">\n          <div class=\"option\" data-answer=\"A\">A) a\/b<\/div>\n          <div class=\"option\" data-answer=\"B\">B) b\/a<\/div>\n          <div class=\"option\" data-answer=\"C\">C) a\u00b2\/b\u00b2<\/div>\n          <div class=\"option\" data-answer=\"D\">D) b\u00b2\/a\u00b2<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation2\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: b\/a, using V = \u03c3R\/\u03b5\u2080.<\/p>\n      <\/div>\n    <\/div>\n\n    <!-- QUIZ 6 -->\n    <div class=\"page-container\" id=\"quiz6\">\n      <div class=\"main-content\">\n        <p>Q&#8211;1: Two spheres A and B of radius &#8216;a&#8217; and &#8216;b&#8217; are at same electric potential. The ratio of surface charge densities is:<\/p>\n        <div id=\"options6\">\n          <div class=\"option\" data-answer=\"A\">A) a\/b<\/div>\n          <div class=\"option\" data-answer=\"B\">B) b\/a<\/div>\n          <div class=\"option\" data-answer=\"C\">C) a\u00b2\/b\u00b2<\/div>\n          <div class=\"option\" data-answer=\"D\">D) b\u00b2\/a\u00b2<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation6\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: b\/a, using V = \u03c3R\/\u03b5\u2080.<\/p>\n      <\/div>\n    <\/div>\n  <\/details>\n\n\n  <!-- SUB-CATEGORY 3 (NEW) -->\n  <details>\n    <summary>Simple\/Direct Formulas Asked<\/summary>\n\n    <!-- QUIZ 4 -->\n    <div class=\"page-container\" id=\"quiz4\">\n      <div class=\"main-content\">\n        <p>Q&#8211;1: Which of the following is the correct mathematical statement of Gauss\u2019s Law?<\/p>\n        <div id=\"options4\">\n          <div class=\"option\" data-answer=\"A\">A) \u222eE\u00b7dl = Q\/\u03b5\u2080<\/div>\n          <div class=\"option\" data-answer=\"B\">B) \u222eE\u00b7dA = Q\/\u03b5\u2080<\/div>\n          <div class=\"option\" data-answer=\"C\">C) \u222eB\u00b7dA = \u03bc\u2080Q<\/div>\n          <div class=\"option\" data-answer=\"D\">D) \u222eF\u00b7dr = W<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation4\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: \u222eE\u00b7dA = Q\/\u03b5\u2080.  \n        Gauss\u2019s Law relates the total electric flux through a closed surface to the charge enclosed.<\/p>\n      <\/div>\n    <\/div>\n\n    <!-- QUIZ 5 -->\n    <div class=\"page-container\" id=\"quiz5\">\n      <div class=\"main-content\">\n        <p>Q&#8211;2: Coulomb\u2019s force law in vector form is:<\/p>\n        <div id=\"options5\">\n          <div class=\"option\" data-answer=\"A\">A) F = k q\u2081q\u2082 \/ r\u00b2<\/div>\n          <div class=\"option\" data-answer=\"B\">B) F = (1\/4\u03c0\u03b5\u2080)(q\u2081q\u2082\/r\u00b2) r\u0302<\/div>\n          <div class=\"option\" data-answer=\"C\">C) F = qE<\/div>\n          <div class=\"option\" data-answer=\"D\">D) F = k q\u2081q\u2082 r\u00b2<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation5\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: F = (1\/4\u03c0\u03b5\u2080)(q\u2081q\u2082\/r\u00b2) r\u0302.  \n        This is Coulomb\u2019s inverse-square law in vector form.<\/p>\n      <\/div>\n    <\/div>\n  <\/details>\n<\/details>\n\n<!-- ================= THEORY-BASED QUESTIONS ================= -->\n<details>\n  <summary>Theory-Based Questions<\/summary>\n  <details>\n    <summary>Figure-based Conceptual Reasoning<\/summary>\n\n  <\/details>\n<\/details>\n\n<!-- ================= NUMERICAL-BASED QUESTIONS ================= -->\n<details>\n  <summary>Numerical-Based Questions<\/summary>\n    <!-- QUIZ 1 -8 Sep 2025 -->\n    <div class=\"page-container\" id=\"quiz1\">\n      <div class=\"main-content\">\n        <p>Q&#8211;1: How much heat energy should be added to a mixture of 10 g of hydrogen and 40 g of helium to change the temp. by 50\u2218C kept in a closed vessel? Given R = 2 cal\/mole K\n<\/p>\n        <div id=\"options1\">\n          <div class=\"option\" data-answer=\"A\">A) 2500 cal<\/div>\n          <div class=\"option\" data-answer=\"B\">B) 2750 cal<\/div>\n          <div class=\"option\" data-answer=\"C\">C) 2000 cal<\/div>\n          <div class=\"option\" data-answer=\"D\">D) None<\/div>\n        <\/div>\n      <\/div>\n      <div id=\"explanation1\" class=\"explanation hidden\">\n        <h3>Explanation<\/h3>\n        <p>Correct answer: 2750 cal (Vm or N\u00b7m\u00b2\/C). <a href=\"https:\/\/learn-by-animation.com\/?page_id=213\">check out the animation for this!<\/a>\n<br>To calculate the heat energy that should be added to a mixture of hydrogen and helium to raise its temperature by 50\u00b0C in a closed vessel, the following steps are taken:<\/br>\n\n<br>1. Determine the number of moles of each gas:<\/br>\n\n<br>The molar mass of hydrogen (H\u2082) is approximately 2 g\/mol .<\/br>\n\n<br>The number of moles of hydrogen is: 10 g \/ 2 g\/mol = 5 moles.<\/br>\n\n<br>The molar mass of helium (He) is approximately 4 g\/mol .<\/br>\n\n<br>The number of moles of helium is: 40 g \/ 4 g\/mol = 10 moles.<\/br>\n\n<br>2. Identify the molar specific heat at constant volume (Cv) for each gas:<\/br>\n\n<br>Since the gas is in a closed vessel, the volume is constant, and we use the molar specific heat at constant volume.<\/br>\n\n<br>Hydrogen is a diatomic gas, so its molar specific heat at constant volume (Cv) is (5\/2)R.<\/br>\n\n<br>Given R = 2 cal\/mol K, the Cv for hydrogen is (5\/2) * 2 = 5 cal\/mol K.<\/br>\n\n<br>Helium is a monatomic gas, and its molar specific heat at constant volume (Cv) is (3\/2)R.<\/br>\n\n<br>The Cv for helium is (3\/2) * 2 = 3 cal\/mol K.<\/br>\n\n<br>3. Calculate the heat energy required for each gas:<\/br>\n\n<br>The formula to calculate the heat energy (\u0394Q) required to change the temperature of a gas at constant volume is \u0394Q = n * Cv * \u0394T, where &#8216;n&#8217; is the number of moles, &#8216;Cv&#8217; is the molar specific heat at constant volume, and &#8216;\u0394T&#8217; is the change in temperature.<\/br>\n\n<br>For hydrogen: \u0394Q_H\u2082 = 5 moles * 5 cal\/mol K * 50 K = 1250 cal.<\/br>\n\n<br>For helium: \u0394Q_He = 10 moles * 3 cal\/mol K * 50 K = 1500 cal.<\/br>\n\n<br>4. Calculate the total heat energy:<\/br>\n\n<br>The total heat energy required is the sum of the heat energy required for each gas.<\/br>\n\n<br>Total \u0394Q = \u0394Q_H\u2082 + \u0394Q_He = 1250 cal + 1500 cal = 2750 cal.<\/br>\n\n<br>Therefore, 2750 calories of heat energy should be added to the mixture to increase its temperature by 50\u00b0C.<\/br>\n<\/p>\n      <\/div>\n    <\/div>\n  <details>\n    <summary>Figure-based Numericals<\/summary>\n    <p>[You can add quizzes here same way as above]<\/p>\n  <\/details>\n<\/details>\n\n<script>\n\/\/ QUIZ 1\n(() => {\n  const correctAnswer = 'B';\n  const options = document.querySelectorAll('#options1 .option');\n  const explanationDiv = document.getElementById('explanation1');\n  options.forEach(opt => opt.addEventListener('click', () => {\n    const selected = opt.getAttribute('data-answer');\n    opt.classList.add(selected === correctAnswer ? 'correct' : 'incorrect');\n    explanationDiv.classList.remove('hidden');\n    options.forEach(o => o.style.pointerEvents = 'none');\n  }));\n})();\n\n<\/script>\n\n<\/body>\n<\/html>\n","protected":false},"excerpt":{"rendered":"<p>The Multiple Choice Questions with solutions are divided into three categories: Question Bank Question Bank Formula-Based Questions SI Units Asked Q&#8211;2: The SI unit of Electric Field is: A) Volt\/meter B) Newton C) Joule D) Coulomb Explanation Correct answer: Volt\/meter (same as Newton per coulomb). Derived Formulas Asked Q&#8211;1: Two spheres A and B of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"footnotes":""},"class_list":["post-231","page","type-page","status-publish","hentry"],"_links":{"self":[{"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/pages\/231","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=231"}],"version-history":[{"count":6,"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/pages\/231\/revisions"}],"predecessor-version":[{"id":247,"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=\/wp\/v2\/pages\/231\/revisions\/247"}],"wp:attachment":[{"href":"https:\/\/learn-by-animation.com\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=231"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}